In a class of 48 students, if there are twice as many girls as boys, how many boys are there?

In a class of 48 students, if there are twice as many girls as boys, how many boys are there?

• A. 15
• B. 16
• C. 24
• D. 32

Answer: (B)

To determine the number of boys in the class, we can set up a relationship based on the information given: there are twice as many girls as boys. Let the number of boys be represented by a variable, say \( b \). According to the problem, then the number of girls would be \( 2b \). The total number of students in the class is the sum of the number of boys and girls, which can be expressed as: \[ b + 2b = 48 \] This simplifies to: \[ 3b = 48 \] To find the value of \( b \), we divide both sides by 3: \[ b = \frac{48}{3} = 16 \] Thus, there are 16 boys in the class. Given the relationship where the number of girls is twice the number of boys, the number of girls would then be \( 2 \times 16 = 32 \). The total is verified as \( 16 \) boys plus \( 32 \) girls, equaling \( 48 \) students. Therefore, the correct number of boys in the class is 16.

To determine the number of boys in the class, we can set up a relationship based on the information given: there are twice as many girls as boys.

Let the number of boys be represented by a variable, say ( b ). According to the problem, then the number of girls would be ( 2b ).

The total number of students in the class is the sum of the number of boys and girls, which can be expressed as:

[ b + 2b = 48 ]

This simplifies to:

[ 3b = 48 ]

To find the value of ( b ), we divide both sides by 3:

[ b = \frac{48}{3} = 16 ]

Thus, there are 16 boys in the class. Given the relationship where the number of girls is twice the number of boys, the number of girls would then be ( 2 \times 16 = 32 ).

The total is verified as ( 16 ) boys plus ( 32 ) girls, equaling ( 48 ) students. Therefore, the correct number of boys in the class is 16.